only_unique_device_id

Description:

only unique device id

unique_device_id #
A flutter plugin that can get a unique deviceId
use #
import 'package:only_unique_device_id/only_unique_device_id.dart' as OnlyUniqueDeviceId;

Future<String?> get_only_unique_device_id() async {
// ignore: non_constant_identifier_names
String? UniqueDeviceId =
await OnlyUniqueDeviceId.OnlyUniqueDeviceId().getOnlyUniqueDeviceId();
print(UniqueDeviceId);
return UniqueDeviceId;
}
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About android #
I know there isn't any 'perfect' way of getting a unique ID without using permissions; however, sometimes we only really need to track the device installation. When it comes to creating a unique ID, we can create a 'pseudo unique id' based solely on information that the Android API gives us without using extra permissions. This way, we can show the user respect and try to offer a good user experience as well.
how does it work?
private String getUniquePsuedoID() {
// If all else fails, if the user does have lower than API 9 (lower
// than Gingerbread), has reset their device or 'Secure.ANDROID_ID'
// returns 'null', then simply the ID returned will be solely based
// off their Android device information. This is where the collisions
// can happen.
// Thanks http://www.pocketmagic.net/?p=1662!
// Try not to use DISPLAY, HOST or ID - these items could change.
// If there are collisions, there will be overlapping data
String m_szDevIDShort = "35" + (Build.BOARD.length() % 10) + (Build.BRAND.length() % 10) + (Build.CPU_ABI.length() % 10) + (Build.DEVICE.length() % 10) + (Build.MANUFACTURER.length() % 10) + (Build.MODEL.length() % 10) + (Build.PRODUCT.length() % 10);

// Thanks to @Roman SL!
// https://stackoverflow.com/a/4789483/950427
// Only devices with API >= 9 have android.os.Build.SERIAL
// http://developer.android.com/reference/android/os/Build.html#SERIAL
// If a user upgrades software or roots their device, there will be a duplicate entry
String serial = null;
try {
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
serial = android.os.Build.getSerial();
} else {
serial = Build.SERIAL;
}
// Go ahead and return the serial for api => 9
return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
} catch (Exception exception) {
// String needs to be initialized
final String androidId = "" + android.provider.Settings.Secure.getString(_flutterPluginBinding.getApplicationContext().getContentResolver(), android.provider.Settings.Secure.ANDROID_ID);
serial = androidId;
}

// if Build.SERIAL get successfuly, the 'id' is unique very likely, if not, we use androidId to guarante 'id' to be unique as possible
// without any permissions


// Thanks @Joe!
// https://stackoverflow.com/a/2853253/950427
// Finally, combine the values we have found by using the UUID class to create a unique identifier
return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
}
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About ios #
CFUUID + KeyChain
Getting Started #
This project is a starting point for a Flutter
plug-in package,
a specialized package that includes platform-specific implementation code for
Android and/or iOS.
For help getting started with Flutter, view our
online documentation, which offers tutorials,
samples, guidance on mobile development, and a full API reference.
Thanks #

is-there-a-unique-android-device-id
FCUUID
UICKeyChainStore

only_unique_device_id #
A new Flutter plugin project.
Getting Started #
This project is a starting point for a Flutter
plug-in package,
a specialized package that includes platform-specific implementation code for
Android and/or iOS.
For help getting started with Flutter development, view the
online documentation, which offers tutorials,
samples, guidance on mobile development, and a full API reference.
only_unique_device_id #